Ответы к учебнику по математике за 2 класс 2 часть Рудницкая. Нахождение нескольких частей числа. Номер №13

Вычисли.
(92 − 29) : 7
(6 * 6) : 9
(60 + 37) − 27
81 : (40 − 31)
(27 + 21) : 6​​​​​​​
(56 : 8) * 4
(40 − 16) : 8
0 : (96 − 89)
35 + 35
70 − 28
65 * 0
42 : (2 * 3)

Ответ

(92 − 29) : 7 = 9
(6 * 6) : 9 = 4
(60 + 37) − 27 = 70
81 : (40 − 31) = 9
(27 + 21) : 6​​​​​​​ = 8
(56 : 8) * 4 = 28
(40 − 16) : 8 = 3
0 : (96 − 89) = 0
35 + 35 = 70
70 − 28 = 42
65 * 0 = 0
42 : (2 * 3) = 7
Вычисления:
(92 − 29) : 7 = 63 : 7 = 9

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}92\\ 29\end{array}}\\ \begin{array}{r}63\end{array}\end{array}$
(6 * 6) : 9 = 36 : 9 = 4
(60 + 37) − 27 = 97 − 27 = 70

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}60\\ 37\end{array}}\\ \begin{array}{r}97\end{array}\end{array}$

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}97\\ 27\end{array}}\\ \begin{array}{r}70\end{array}\end{array}$
81 : (40 − 31) = 81 : 9 = 9

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}40\\ 31\end{array}}\\ \begin{array}{r}9\end{array}\end{array}$
(27 + 21) : 6​​​​​​​ = 48 : 6 = 8

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}27\\ 21\end{array}}\\ \begin{array}{r}48\end{array}\end{array}$
(56 : 8) * 4 = 7 * 4 = 28
(40 − 16) : 8 = 24 : 8 = 3

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}40\\ 16\end{array}}\\ \begin{array}{r}24\end{array}\end{array}$
0 : (96 − 89) = 0 : 7 = 0

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}96\\ 89\end{array}}\\ \begin{array}{r}7\end{array}\end{array}$
35 + 35​​​​​​​ = 70

$\begin{array}{r}\begin{array}{r}+\end{array}\underline{\begin{array}{r}35\\ 35\end{array}}\\ \begin{array}{r}70\end{array}\end{array}$
70 − 28 = 42

$\begin{array}{r}\begin{array}{r}—\end{array}\underline{\begin{array}{r}70\\ 28\end{array}}\\ \begin{array}{r}42\end{array}\end{array}$
65 * 0 = 0
42 : (2 * 3) = 42 : 6 = 7